Review of Solid Mechanics III
1. Introduction to Bending
- Beam
- A structural member subjected to loads acting laterally to its longitudinal axis.
- Compare with truss structures that primarily carry axial loads.
- Pure Bending
- Bending moment ( M ) is constant.
- Shear force ( Q ) is zero.
2. Strains in Beams
Curvature and Geometry
-
Curvature ( \kappa ):
[ \kappa = \frac{1}{\rho} ]
where ( \rho ) is the radius of curvature. -
For small deflections:
[ \frac{d\theta}{dx} = \kappa ]
( \theta ): slope or angle of rotation of the beam.
Axial (Normal) Strains
-
Assumption (Euler-Bernoulli beam theory):
Cross-sections remain plane and perpendicular to longitudinal axis after deformation. - Tension: Upper part of the beam.
- Compression: Lower part of the beam.
-
Neutral Surface: No change in length.
- Axial strain ( \varepsilon_x ):
[ \varepsilon_x = -y \kappa ]
where ( y ): distance from the neutral axis.
3. Stresses in Beams
Axial (Normal) Stress
-
Hooke’s Law for beams:
[ \sigma_x = E \varepsilon_x = -E y \kappa ] -
Tensile stress (positive) and compressive stress (negative) depend on ( y ).
Transverse Strains
- Poisson effect introduces transverse strains:
[ \varepsilon_z = -\nu \varepsilon_x = \nu y \kappa ]
4. Force and Moment Equilibrium in Pure Bending
-
Resultant axial force is zero:
[ \int_A \sigma_x \, dA = 0 ] -
Resultant moment about neutral axis:
[ M = \int_A \sigma_x y \, dA = -E \kappa \int_A y^2 dA = -E \kappa I ] -
Stress distribution:
[ \sigma_x = -\frac{M}{I} y ] -
Maximum stress occurs at the largest ( |y| ):
[ \sigma_{max} = \frac{M y_{max}}{I} ]
5. Beams with Axial Loads
- Combined axial force ( N ) and bending moment ( M )**:
[ \sigma = \frac{N}{A} + \frac{M y}{I} ]
Eccentric Axial Loads
-
Axial force ( P ) applied at a distance ( e ):
[ \sigma = \frac{P}{A} + \frac{P e y}{I} ] -
Statically equivalent to a centrally applied force plus a moment ( Pe ).
6. Deflections of Beams
Basic Geometry
- ( \kappa = \frac{d\theta}{dx} = \frac{d^2 v}{dx^2} )
- Slope ( \theta \approx \tan \theta = \frac{dv}{dx} )
Differential Equations of the Deflection Curve
- Curvature relates to moment:
[ \kappa = \frac{M}{EI} ]
Therefore:
[ \frac{d^2 v}{dx^2} = \frac{M}{EI} ]
And further:
[ \frac{d^3 v}{dx^3} = \frac{V}{EI} ]
[ \frac{d^4 v}{dx^4} = \frac{q}{EI} ]
Example Exercise
- Simply supported beam under uniform load ( q ):
- Moment equation:
[ M(x) = -\frac{q}{2}(Lx - x^2) ] - Deflection equation:
[ v(x) = \frac{q}{24 EI} (x^4 - 2L x^3 + L^2 x^2) ] - Maximum deflection at ( x = \frac{L}{2} ).
- Moment equation:
7. Plane Stress vs. Plane Strain
Plane Stress | Plane Strain | |
---|---|---|
Stress | ( \sigma_{zz} = 0 ) | ( \varepsilon_{zz} = 0 ) |
Applicable to | Thin plates | Long structures constrained in ( z )-dir |
Constitutive Eq | ( \varepsilon_{zz} = -\frac{\nu}{E}(\sigma_{xx} + \sigma_{yy}) ) | ( \sigma_{zz} = \nu(\sigma_{xx} + \sigma_{yy}) ) |
8. Summary
✅ Key Points
- Strains and stresses in beams under bending.
- Equilibrium conditions for pure bending.
- Deflection curves and equations.
- Difference between plane stress and plane strain conditions.
9. Preview of Next Topics
- FEM (Finite Element Method) for structural analysis.
- Real-world applications:
- Complex geometries and loading conditions.
- Use of computational tools (PCs, supercomputers).